ereg problem

asa_carter

Hi,

Can anyone see what is wrong with this ereg for checking for a valid dd-mm-yyyy


if (!ereg("^\d\d[-]\d\d[-]\d\d\d\d$",$checkin))
  $err2=1;

if ($err2==1)
  echo "Please enter a valid check in date {dd-mm-yyyy}.<br>";

Thanks

Asa.

bodzan

You could enter a date like 55-99-9076 or whetever and if ereg works like you imagined it will assume that it is a right formatted string not the date...

I would recommend using checkdate() for date validation...

Although the parameter would have to be set like (mm,dd,yyyy) but thats not a big issue to add to your current code...

And for your code try this:

preg_match("/\d\d[-]\d\d[-]\d\d\d\d/",$checkin)

but I'm not sure whether it will work at all

asa_carter

Hi,

It is really only the string formatting that I want to verify.

I tried preg_match but that didn't work.

I am using a date selector that stores the date as dd-mm rather than mm-dd.

I thought my ereg string would work but it still crates an error when a valid date is entered.

Asa

bodzan

if (ereg ("([0-9]{4})-([0-9]{1,2})-([0-9]{1,2})", $date, $regs)) {
   echo "$regs[3].$regs[2].$regs[1]";
} else {
   echo "Invalid date format: $date";
}

But it can be easilly converted to what you need. However my question would be: why using ^ and $ as delimiters? I don't think that they belong there...

The code above is where the explanation for the ereg() function is, but is there any reason for using the \d syntax?