[Resolved] calendar function gets to 10-30 then keeps repeating 10-30 ??????

[dewcansam]

I hope somebody can help me here. It has been awhile since I programmed in PHP everyday.

I need a function that takes the date and returns the week number of the year. For example you would pass the date 2005-06-19 and it would return 25. I started with a working calendar script and tried to tweak it to return the week number. It worked for a while then for some unknow reason (i must have done something) it would start repeating the date 10-30. Here is what I have so far. Also note that the find date code is not in place here.

This script is by no means optimized.

<?php
$week = date2wk("2005","1","2","2005","6","18"); // should return 24 $week = 24

function date2wk($year, $month, $day, $find_year, $find_month, $find_day)
{
  $x=0;
  for ($wk = 1; $wk <= 53; $wk++)
  {
    for ($b = 1; $b <= 7; $b++)
    {
      $date = mktime("","","",$month, $day, $year);
      echo date('Y-m-d',$date) . "\r\n";
      echo "&nbsp;&nbsp;&nbsp;&nbsp; $x<br>\r\n";$x++;
      $newtime = getdate($date + (60*60*24));
      $year = $newtime["year"];
      $month = $newtime["mon"];
      $day = $newtime["mday"];
    }
  }
}
?>

[Weedpacket]

How do you count week numbers? I'd've put 2005-06-19 into week 24 (a la date('W') and the calendar on my wall, as it happens).

I don't understand what the intentions of your code are well enough to say why it's not doing what it is intended to, but I'm wondering that if you did try to write it more cleanly whether it would make more sense and be easier to debug?

One suggestion (I can't tell whether it would help or not) is to note that mktime(0, 0, 0, 1, 100, 2005) is a perfectly acceptable way of specifying March 10.

[dewcansam]

I needed a function that would take a date and return the week number of the year.
The first week of the year is counted from the first Sunday of the new year for example in 2005 the first sunday is 01-02 so 06-19 is in the 25th week. In 2007 the first Sunday is 01-07 so the first week starts with 01-07. The first FOR loop loops through the week numbers. The second FOR loop loops through the days of the week (537). Note that (527) = 364 AND NOT 365 days that are in a year. You must count up to the 53rd week. Anyways this function works and you can check it out at http://ralresorts.com/beta01/tg/cal.php?y=2005&m=06&d=19 . note the query string, so that you can alter the date and month and it will display the week number. The fubar script still prints out 10-30 and can be seen at http://ralresorts.com/beta01/tg/cal_old.php.
I hope that explains things abit.

<?php
(empty($y))? $y = 2005:"";
(empty($m))? $m = 8:"";
(empty($d))? $d = 16:"";
echo "<h1>found date $y-$m-$d in week # ".date2wk("2005","1","2","$y","$m","$d")."</h1>\r\n";

function date2wk($year, $month, $day, $find_year, $find_month, $find_day)
{
  define("ADAY", (60*60*24));
  define("tab", "&nbsp;&nbsp;&nbsp;&nbsp;");
  $timestamp = mktime(0,0,0,$month,$day,$year);
  //$dayArray = getdate($start);
  $x=1;$tab = "&nbsp;&nbsp;&nbsp;&nbsp;";
  for ($wk = 1; $wk <= 53; $wk++)
  {
    for ($wkday = 1; $wkday <= 7; $wkday++)
    {
      $dayArray = getdate($timestamp);
      if (($find_year == $dayArray['year']) && ($find_month == $dayArray['mon']) && ($find_day == $dayArray['mday']))
      {
        //echo "<h1>found day in week $wk</h1>";
        return $wk;
      }
      //echo "$find_year $tab $find_month $tab $find_day $tab<br>\r\n";
      //echo "$dayArray[year] $tab $dayArray[mon] $tab $dayArray[mday] <br>\r\n";
      //echo date("Y-m-d", $timestamp) . "$tab";
      $timestamp += ADAY;
      //echo "$x $tab week = $wk $tab wkday = $wkday<BR>\r\n";
      $x++;
      if ($x > 365)
      {
        //echo "exiting";
        return 1;
      }
    }
  }
  return 0;
}

?>

[dewcansam]

Final working version.
also note that this script could easily be written to take date in the format of 07/04/07.
To do this convert the params to ($start_year_date, $find_date) then add the code to explode this format

$start_year_date_array = explode("/",$start_year_date);
$year = $start_year_date_array[2];
/*  ..... and so on ..... */

$weekNumber = date2wk(2007,1,7,2007,7,4);

/**************************************
 *  Version: 1.09
 *  Author: Christopher Smith
 *  Purpose: to return the week number of a specific
 *                  date.
 *  param: int 'year' - the year to search
 *  param: int 'month' - the start year month usually 1
 *  param: int 'day' - the start year day depends on
       year and weekday you wish to start counting 
       the weeks by - if the first day of the week is
       sunday and year is 2007 then day would be 7
       2007-01-07 is the first sunday of the new year
 *  param: int 'find_year' - the year you are searching
       should be the same as year - cause if they are
       different the week might not be found
 *  param: int 'find_month' - the month of the date you
       are searching
 *  param: int 'find_day' - the day of the date you
       are searching
 * returns: int - the week number of the year of the
 *   date you are searching
 ******************************************/
function date2wk($year, $month, $day, $find_year, $find_month, $find_day)
{
  define("ADAY", (60*60*24));
  $timestamp = mktime(0,0,0,$month,$day,$year); /* create timestamp from current date */
  for ($wk = 1; $wk <= 53; $wk++) /* loop through the weeks */
  {
    for ($wkday = 1; $wkday <= 7; $wkday++) /* loop through the days in the current week */
    {
      /* create my array for comparing current date to the date i am looking for */
      $dayArray = getdate($timestamp);
      if (($find_year == $dayArray['year'])
        && ($find_month == $dayArray['mon'])
        && ($find_day == $dayArray['mday']))
      {
        return $wk; /* if found the date i was looking for then return the current week */
      }
      $timestamp += ADAY; /* advance the timestamp by 24hrs */
    }
  }
}