Grabbing Images from Directory

raouleduke

I have a image directory that has 05-2416_1, 05-2416_2, etcc...

How do I get all those images if I only know the 05-2416, there could be 1-10 photos for a certain ID.

jansky

my code never tested but you can take a look on it and have some ideas

$imagename="05-2416_"

for ($x=0;$x<10;$x++)
{
$imagenumber++;
$fullname=$imagename.$imagenumber."jpg";
echo "<img src=\"$fullname\" border=\"0\">";
}

raouleduke

Sometimes there are not ten, how can I substitute a blank image or not show it at all.

Matt_Kindig

Check if the file exists with is_file, and if so, show the image.

$imagename="05-2416_"

for ($x=0;$x<10;$x++)
{
$imagenumber++;
$fullname=$imagename.$imagenumber."jpg";
if (is_file($fullname)) {
echo "<img src=\"$fullname\" border=\"0\">";
}
}

raouleduke

That did not work, am I doing something wrong, when I put the is_file in there nothing showes up.

						$imagename = "$ListingID$underscore";

for ($x=0;$x<10;$x++) 
{ 
$imagenumber++; 
$fullname=$imagename.$imagenumber.".jpg"; 
if (is_file('www/htdocs/images/$fullname')) {
echo "<a href=\"javascript:changeImage('images/$fullname')\"><img src=\"images/$fullname\" width='60' height='38' border=\"0\"></a>&nbsp;"; 
}
}

Installer

if (is_file('www/htdocs/images/$fullname'))

PHP doesn't do variable substitution inside single quotes. See here.

Here's another way to do it:

$part_name = '05-2416';
$dir = 'www/htdocs/images';
$dp = dir($dir);
while (($file = $dp->read()) !== false) {
    if (strpos($file, $part_name) === 0) {
        echo $file . '<br />';
    }
}