? Operator acts ambiguously

[delphian7e]

Please run this script, Its output should be two "exactly Seven" but it return One "More than Seven" and one "Exactly Seven!"

I mean the first statement that was written with ? operator does not work properly.

<?
$num = 7;
echo (($num == 7) ? "Exactly Seven!" : ($num > 7) ? "More than Seven!" : "Less than Seven!");
echo "<BR/>";
echo "-------------------------------------------------------------";
echo "<BR/>";
if ($num == 7)
echo "Exactly Seven!";
else if ($num > 7)
echo "More than Seven!";
else
echo "Less than Seven!";
?>

Thanks in advance...

[Drakla]

You're created the ternary version of a 'dangling else', re-bracket like so:

$num = 7;
echo $num == 7 
	? "Exactly Seven!" 	
	: ($num > 7 ? "More than Seven!" : "Less than Seven!");

I reformatted it a sort of clarity