problem with regex in preg_split

[mapg]

I do not understand with this regex doesn't work in PHP and yes in Perl

<?php
$string_prev = "[1|2|3|4][1|2|3|4]";
$array_prev = preg_split("/\[(.*?)\]/", $string_prev);
$string_final = "";
foreach ($array_prev as $string) {
	$string_final .= "[" . $string . "]";
}
echo $string_final; // nothing is printed
print_r($array_prev); // array empty
?>

#!/usr/bin/perl
$string_prev = "[1|2|3|4][1|2|3|4]";
@array_prev = $string_prev =~ /\[(.*?)\]/g;
$string_final = "";
foreach $string (@array_prev) {
	$string_final .= "[" . $string . "]";
}
print "Content-type: text/html\n\n";
print $string_final; # print ... [1|2|3|4][1|2|3|4]

I get with PHP (print_r) an array with 3 elements (instead of 2) and everything is empty.

Something like this ...

Array ( [0] => [1] => [2] => )

In Perl the regular expression is valid. I need help certainly.

Thank you very much in advance

Mapg

[wilku]

If you want to get strings between [ ], shouldn't you use preg_match_all instead of split?
This:

<?php
$string_prev = "[1|2|3|4][1|2|3|4]";
preg_match_all("/\[(.*?)\]/", $string_prev,$array_prev);
$array_prev=$array_prev[1];
$string_final = "";
foreach ($array_prev as $string) {
    $string_final .= "[" . $string . "]";
}
echo $string_final; 
print_r($array_prev);
?>

produces

[1|2|3|4][1|2|3|4]Array ( [0] => 1|2|3|4 [1] => 1|2|3|4 )

[mapg]

Thank you very much Wilku.

You example works great.

Some people told me that I have to use some filters to use the way of preg_split, namely ...

$array_prev = preg_split("/\[(.*?)\]/", $string_prev, -1, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);

I take note about the usage of preg_match_all, as you did.

Thanks. I am leaning a lot.

Mapg