[RESOLVED] work out previous months in drop down

[mfacer]

Hi..
I need to create a drop down menu with a list of months based on the current month... for example, today's month is July - the list should be

Aug 2004
Sept 2004
Oct 2004
Nov 2004
Dec 2004
Jan 2005
Feb 2005
Apr 2005
May 2005
Jun 2005
July 2005
Aug 2005
Sept 2005
Oct 2005
Nov 2005
Dec 2005
Jan 2006
Feb 2006
Apr 2006
May 2006
Jun 2006

So basically I need to list the 10 months before and after the current date.
here's the code I have so far

#if months and years have been sent, use those, otherwise get TODAYs month
if (!$month) { $month = date("m",time()); }
if (!$year)  { $year = date("Y",time());  }

$months_names = array();  #used to store the dates

for ($x=12;$x>($month-10);$x--) {
	#put past months here
}

I just dont know how to actually get the details thought! any help is much appreciated!!

[drew010]

if (!isset($month)) $month = date("M");
if (!isset($year))    $year    = date("Y");

for ($offset = -10; $offset <= 10; ++$offset) {
  echo date("M Y", strtotime("$month $year +$offset months")) . "<br />\n";
}

that should do the trick.

[mfacer]

thanks for the reply... I tried the code above, and it says "Warning: date(): Windows does not support dates prior to midnight (00:00:00), January 1, 1970"

any ideas?

[drew010]

some of the variable must be wrong, cause i tested it on my windows machine and it works fine there, as well as on linux.

[mfacer]

I've tried a few things and nothing worked properly.... so i tried this

for ($offset = -10; $offset <= 10; ++$offset) {
$time = mktime(12, 0, 0, $month, 1, $year);
echo date("M Y", strtotime("+$offset months",$time)) . "<br />\n";
} 

and that worked fine! so there must be a problem with my PHP set up maybe that wasnt creating the time properly??

any hoo - many thanks for your code 🙂 🙂