Converting time to 'days, hours:minutes'

[s_shrum]

I'm trying to 'age' files but can't seem to figure it out.

I'm getting the files modified value and doing:

time() - $mtime;

to get back something like:

18699668

How do I convert this value to 'xdays, yhours:zminutes'?

TIA

[Grisu]

if I understand right, it is a bit tricky. I would first store the time difference as an absolute value:

$yourtime = -($mtime - time()))

Then you can get the days with

$sdays = (int)($yourtime / 3600)

For the hours and minutes you could take

$timedifference = $yourtime - ((int)($yourtime / 3600) * 3600)

and format it with the date() function.

I hope, I do not have a mistake in my thinking. I did not find any character in the date() function that gives back absolute days and I do not know an easier method.

Hope it is of help.

Grius

[s_shrum]

This is what I came up with...it's a variant on someone elses code I found at php.net:

function ElapsedSecondsToString($iSeconds) {
	$yearsDiff = floor($iSeconds/60/60/24/365);
	$iSeconds -= $yearsDiff*60*60*24*365;
	$monthsDiff = floor($iSeconds/60/60/24/30);
	$iSeconds -= $monthsDiff*60*60*24*30;
	$weeksDiff = floor($iSeconds/60/60/24/7);
	$iSeconds -= $weeksDiff*60*60*24*7;
	$daysDiff = floor($iSeconds/60/60/24);
	$iSeconds -= $daysDiff*60*60*24;
	$hrsDiff = floor($iSeconds/60/60);
	$iSeconds -= $hrsDiff*60*60;
	$minsDiff = floor($iSeconds/60);
	$iSeconds -= $minsDiff*60;
	$secsDiff = $iSeconds;
	if ($yearsDiff <> 0) { 
		$sString = $yearsDiff.' year'.(($yearsDiff <> 1) ? "s" : "");
		if ($sString <> "") { $sString = $sString . ", "; }
	}
	if ($monthsDiff <> 0) { 
		$sString = $sString . $monthsDiff.' month'.(($monthsDiff <> 1) ? "s" : "");
		if ($sString <> "") { $sString = $sString . ", "; }
	}
	if ($weeksDiff <> 0) {
		$sString = $sString . $weeksDiff.' week'.(($weeksDiff <> 1) ? "s" : "");
		if ($sString <> "") { $sString = $sString . ", "; }
	}
	if ($daysDiff <> 0) {
		$sString = $sString . $daysDiff.' day'.(($daysDiff <> 1) ? "s" : "");
		if ($sString <> "") { $sString = $sString . ", "; }
	}
	if ($hrsDiff <> 0) { 
		$sString = $sString . $hrsDiff.' hour'.(($hrsDiff <> 1) ? "s" : "");
		if ($sString <> "") { $sString = $sString . ", "; }
	}
	if ($minsDiff <> 0) { 
		$sString = $sString . $minsDiff.' minute'.(($minsDiff <> 1) ? "s" : "");
		if ($sString <> "") { $sString = $sString . ", "; }
	}
	if ($secsDiff <> 0) { $sString = $sString . $secsDiff.' second'.(($secsDiff <> 1) ? "s" : ""); }
	return $sString;
}

[Atomiku]

$foo = time() - $mtime;
date("D/M/Y",$foo);

You will need to goto http://php.net/date though to find out what the Hours and seconds thing is

[Grisu]

sorry, Atomiku, but you did not understand the question. The target is to get the days (and hours and minutes) that something is old. This means the difference from today to sometime in the past in days, hours and minutes. It is not that easy 🆒

[Atomiku]

Ahh, I see.

Couldnt you do some more subtraction then?

Like umm...

Ahh bugger I cant do it 😛

Slowly walks away abit... Then runs