How do display different images if user logged in/out

[Scorpio___]

Hello guys,

Firstly i would like to say hello to everyone! 🙂

I run a chat site with members profiles that allows members to email each other by clicking a link on a members profile page.

I have already written a script that displays an image link (when a user is logged in) to appear on a members profile page to allow members to contact each other.

However, it only shows up when the member is logged in, how do i get a different image or text link to show if the guest/member is not logged in?

eg.
When the member has logged in an image link says 'send message' but when a member is not logged in it shows a text link saying 'login to send message'

My guess is this needs to be an 'if something = ' ' then echo this instead' statement?

Heres the code that displays an image when a member has logged in but how to i get it to display a different image when there not logged in? (at the moment it displays an empty space where the image should be).

<?
$tmp=mysql_query("SELECT * FROM ".C_MYSQL_MEMBERS." WHERE id='".$_SESSION['m']."'");
while($i=mysql_fetch_array($tmp)){
$name = ($i['email']);
$password = ($i['password']);
echo "<input type=hidden name=username value=".$name."><input type=hidden name=password value=".$password."><input type=image src=members/sendamessage.gif alt='send a message'>";}
?>

Might be easier to see what i am talking about by visiting my website! 🙂 lol
http://www.swindonchat.co.uk/members

Any help would be appreciated.

Thank you!

[trex005]

if(User_logged_in)
{
     echo "image and text code for if they are logged in";
}
else
{
     echo "image and text code for if they are not logged in";
}

that is the basic syntax... not sure if that is what you are looking for.