PHP With HTML

vijaykoul

I have a problem making PHP work to its full. i have installed php 5.x version, apache 1.3.x ver and mysql 3.x version

all of them are working fine. i have a problem....
when i pass any hidden variable within a form like in the code below

<?
if ($chk == "yes")
{
echo "hi";
}
?>
<form>
<input type="hidden" name="chk" value="yes">
<input type="submit" value="submit">
</form>

now, when i press this submit button, instead of getting "hi" as the output, i get an error which reads as

undefined variable "chk"

i tried to solve this problem many a times, but cant. i even reinstalled php...but that did not solve the purpose....

can anybody help me... please..
thanks in advance....

vijay koul

thorpe

you have register_globals switched off (recommended), try this.

if ($_POST['chk'] == "yes")

then you need to read up in the manual on the use of global variables.

vijaykoul

i tried
if($_POST['submit'])
{
echo "hi"
}

it gave the same error, submit undefined

ahundiak

Change:
<input type="submit" value="submit">
To:
<input type="submit" name="submit" value="submit" />
Understand that $POST['submit'] will only be defined when the page is actually posted. There are several ways to check if a page is being posted but:
if (isset($POST['submit'])) {
will work.

jabba_29

Your form, since it has no method, will default to $_GET.. so you need to check against that...it should be in your URL....