making third element in array =0

[nicky77uk1]

Array ( [2005-08-21] => 20 [2005-08-22] => 20 [2005-08-23] => 20 [2005-08-24] => 20 [2005-08-25] => 20) 

The above is my array, the day of each date is sun(21), mon(22), tue(23), weds(24), thurs(25).

i use the code below which reports back the day of the week of each day

$day = date('w', $dates);
output

1
2
3
4

what i want to do is somehow to make the third element in the array = 0 if the first two elements that falls on a day between 0 and 4 (sun and thurs)

i.e
if the days are 0,1,2,3 then 2 should = 0
or
if the days are 3,4,5,6,0 then 0 should = 0

any ideas?

[thorpe]

$arr[2] = 0;

[nicky77uk1]

what i want is it to be conditional. please read above.

for instance lets say an array[0]=20 20 20 20 20
i would like the 3rd time the value=20 to be 0
result:the 3rd element would=0 (array[0]=20 20 0 20 20)

so if an array[0]=20 30 20 20 20
result: the 4th element would=0 (array[0]=20 30 20 0 20)

cheers!

[Maiku]

So, you want a zero at the third place a specified element is encountered in the array? If that's what you want, excuse the inelegant solution below:

$yourArray = array(20, 20, 30, 20, 20);
$specifiedElement = 20;
$elementCount = 0;

for ($i = 0; $i < $yourArray.count(); @i++)
{
      if ($yourArray[$i] == $specifiedElement)
            $elementCount++;

  if ($elementCount == 3)
  {
        $yourArray[$i] = 0;
        break;
  }
}
// Would exit loop with $yourArray equals to (20, 20, 30, 0, 20)
// You could also remove the break statement to change every third 20 in the array to 0

[Weedpacket]

[man]array_keys[/man]. Use that to search for 20. The array returned is a list of the keys in the original array that pair up with the value 20. The third element in that list of keys is the one you want.

[nicky77uk1]

thanks for the reply but the $specifiedElement = is variable.

it could be 45...

what i want to do is test for a value that occurs more then 3 times and on the 3rd time i want it to = 0