[RESOLVED] php equivalent to typeof operator?

[printelectric]

I get the feeling that the answer is 'no', because I sure can't find it...

Is there a PHP equivalent to the typeof operator?

For instance, I want to know if $bar is an integer or not...

function foo($bar) {
if (typeof($bar) == integer) {
// do some stuff
} else {
echo('gimme an integer!');
exit;
}
} // end foo

Thanks in advance. I know this is a dumb noob question - it just seems like if this method doesn't exist, somebody's gotta have a hack for it by now..

[konsu]

would isinteger work? (or is it is_integer()?)

[mrhappiness]

[man]is_integer[/man], [man]gettype[/man]

but be careful:

$a = 1;
$b = "1";
if (is_integer($a))
  echo '$a is an integer';
else
  echo '$a is not an integer';
echo '<br />';
if (is_integer($b))
  echo '$b is an integer';
else
  echo '$b is not an integer';
echo '<br />';
echo 'type of $a: '.gettype($a).'<br />';
echo 'type of $b: '.gettype($b);

output:

$a is an integer
$b is not an integer
type of $a: integer
type of $b: string

maybe you're looking for [man]is_numeric[/man] or you want to convert the var to an integer:

$a = '1';
$b = (int)$a;

[printelectric]

Thanks.

[superwormy]

is_integer()
is_numeric()
is_array()
get_class()
etc.

[Sayian]

I guess you could also use some form of a regular expression check for this as well ... define what you want to allow , then check against it

$match = define the regular expression to check on here ..

if(!$match) {
// do stuff
} else {

// do stuff

}

[DynV]

For the original sample code, you could've used gettype

[bradgrafelman]

Another alternative:

if ($bar === (int)$bar) {
    // it's an integer
} else {
    // not an integer
}