search and replace all

[joeblock]

Hi,

Here's a simple question

How can I do the following:

$string = "href="../../../test1/testing/test.html";
or
$string = "href="../../testing/test.html";

change string to get rid of the beginning
so that

$string = 'href='http://www.mysite.com/testing/test.html"';

$string could have multiple href.

Thank you

[drew010]

$string = preg_replace('/(\.\.\/)+/', 'http://'.$_SERVER['HTTP_HOST'].'/', $string);

something along those lines.

[joeblock]

Hi Drew,

Thanks for the code.

but how do I get rid of the test1 in
$string = "href="../../../test1/testing/test.html";

I get:
href="http://www.mysite.com/test1/testing/test.html"

it should be :

href="http://www.mysite.com/testing/test.html"

I guess I am asking for a way to search for href=" and /testing and replace it with
href="http://www.mysite.com/testing

Thanks for your help

Sorry to ask such simple questions.. I just do not understand these REGEX stuff!

[cyberlew15]

a literal str_replace would work, you could do an if substr ../../../test1/ is in the link replace ../../../test1/ with http://www.mysite.com/ and if substr ../../testing is in the link replace it with http://www.mysite.com/testing

it's really easy and the php dot net website will tell you enough about substr and str_replace so that you can write this script. you may want it to open all of the files within the directory and then open them and replace the selected text

[joeblock]

The problem is that there are multiple href in the string and it can be any number of characters

between href and testing.

like:

href="XXXXXXXXXXXX/testing/test.html"

so it would have to be a preg_replace or ereg_replace.