[RESOLVED] Why does this throw a nondescriptive parse error?

[ppowell]

if (is_array($this->getResult()) && sizeof($this->getResult()) > (int)$displayItemLimit) {
 // DO STUFF
}

This throws a parse error (and doesn't describe it anymore than a parse error), however, this works:

if (is_array($this->getResult()) && sizeof($result) > (int)$displayItemLimit) {
 // DO STUFF
}

Even setting to a local variable will break it!! What on earth???!?!

Phil

[maxpup979]

looks like bad syntax to me...
use parenthesis to tell PHP what you really mean....

if (is_array($this->getResult()) &&(sizeof($this->getResult()) > (int)$displayItemLimit)){
#whatever
}

[ppowell]

OK this is getting weirder:

		$fullResult = $this->getResult();
		if ($willPaginate && (int)$displayItemLimit > 0 && !$willShowAllPages && is_array($fullResult) && @sizeof($fullResult) > (int)$displayItemLimit) { 
                   // DO STUFF
                }

This produces a parse error (no further information), but this works:

		$fullResult = $this->getResult();
		if ($willPaginate && (int)$displayItemLimit > 0 && !$willShowAllPages && is_array($fullResult) && @sizeof($result) > (int)$displayItemLimit) {
                 // DO STUFF
                }

How can one variable produce a parse error, while another be just fine?

Phil

[Weedpacket]

None of the pieces of code you've posted give me a parse error.
test.php

<?php
$fullResult = $this->getResult();
        if ($willPaginate && (int)$displayItemLimit > 0 && !$willShowAllPages && is_array($fullResult) && @sizeof($fullResult) > (int)$displayItemLimit) { 
                   // DO STUFF
                }  

?>

php -l test.php
No syntax errors detected in test.php

[ppowell]

I fixed it. It wasn't the code I sent you after all, but for some reason it kept reporting on that line. Turns out it was a class method somewhere else that had a bad line in it.

Phil