How to get the output from outside call???

cyanblue

Howdy... 🙂

I need to call a script that is sitting in somebody else's domain and utilize that value...

For example, I am calling http://www.notmydomain.com/echo.php which basically does echo("hello");

and my script would be something like this...

$output1 = "Some output from my script...";
$output2 = getOutput("http://www.notmydomain.com/echo.php");
// This URL could be some something.html or something.txt...
echo("Output #1 is " . $output1 . " and output #2 is " . $output2);

function getOutput() { /* I have no clue... */ }

Any idea???

Thanks... 🙂

maxpup979

user fopen to grab the page from their site. then parse to get the info you need.

cyanblue

Correct me if I am wrong, but I thought that fopen will not execute the PHP file??? Or am I just wrong about that??? Of course, I have no doubt that will work with the text file...

maxpup979

I am assuming that you are opening a page on a website. Something you can see with a browser. If that is the case then....

Ya...you are wrong...🙂

frymaster

cyanblue wrote:
Correct me if I am wrong, but I thought that fopen will not execute the PHP file??? Or am I just wrong about that??? Of course, I have no doubt that will work with the text file...

fopen will not execute the php file... but apache/mod_php will on the other persons domain. when you use the file functions on a web page what you're reading is the end html of that page, ie the output after the php has been executed just as it would appear in your browser if you typed the url into the address bar.

cyanblue

Ah... Yes... That makes sense... If I was right, anybody can copy somebody else's source code... What was I thinking??? 😃

Thanks, guys... 🙂

maxpup979

they can copy the HTML output, but not the actual source code (unless the file itself is exposed...)