[RESOLVED] want a different page to load according to checkbox

[kingman65]

Would someone please help me with this? I have been trying to resolve this for a couple of days and I have tried using info I found on this board, but I am getting no closer.
I have a form with a single checkbox. If the user checks it, I want the orderthanks incl. to be returned. If they do not check it, then I want orderthanks2 incl to be returned. I am trying the isSet statement below. If I do it this way then it always loads the first inc. file. If I try it with just the second if statement alone, then it returns the 2nd include, but not the first. When the box is checked the value returned is 'on', I have tried it using that as well, does not work. I am sure there is something simple that I am missing. Any help would be greatly appreciated.

<?

if (isSet($_POST['add_ccinfo']) && $_POST['$add_ccinfo == 1'])
{
	$add_ccinfo = 1;
}else{
	$add_ccinfo = 0;
}

if ($add_ccinfo == 1)
{
	include("pages/order_thanks.inc.php");
}else{
	include("pages/order_thanks2.inc.php");
}

?>

[rikmoncur]

<form name="form1" method="post" action="">
<input type="checkbox" name="BoxValue" value="1">
<input type="submit" name="Submit" value="Submit">
</form>

<?php
$result = $_POST['BoxValue'];
if (isset($Submit)){
if ($result == 1)
{include('thanx1.php');}
else
{include('thanx2.php');}
}

?>

[kingman65]

Ok, I tried your technique and it does not load either page now. I tried enclosing the include in single quotes the way you have it. I also tried double quotes. Same result. The way I had it originally, it would return the include, but could not decide which one to return. The way you suggest, it returns a blank page. I have also tried with the value set to 'on' and '1'. Neither option makes a difference

<?
$result = $_POST['add_ccinfo'];
if (isSet($Submit))
{	
   if ($result == on)
{
	include('pages/order_thanks.inc.php');
   }else{
	include('pages/order_thanks2.inc.php');
}
}
?>		

[kingman65]

If I remove the conditional:

if (isSet($Submit)) 
{
}

Then it will load the incl. statement, but it still loads just the one and won't change if I uncheck the box

[kburger]

if ($result == "on") Enclose your string in quotes.

rikmoncur's code should work perfectly.

[Weedpacket]

Although you may want to try isset($POST['Submit']) - Newbies Forum FAQ, Question One. (Or is that $POST['submit']? I can never remember case-sensitivity when it comes to these things. I just do it all lower case and be done with it.)

[kingman65]

putting the string in quotes and removing the isSet function did the trick. Thanks alot guys!