Generated thumbnail link open in a new window?

David448

I have a script that generates a thumbnails of all the images in a givin' directory. This thumbnail is also a link to the full size image.

My problem is, I would MUCH prefer if this link, was a target blank, or 'open in a new window'. I cannot figure it out.

I think this is the area of the code that I have to edit:

	if ($useAutoThumbnails && $f["filetype"]=="image") {
		$f["thumbnail"] = "<a href=\"".urldecode($f["link"])."\"><img src=\"".$PHP_SELF."?thumbnail=".urlencode($path.$f["name"])."\" style=\"text-align: left;\" alt=\"\"/></a>";
	}

I'm not positive though as there are so many calls for 'thumbnail'.

Any help appriciated.

rikmoncur

What would happen if you did this:


 if ($useAutoThumbnails && $f["filetype"]=="image") { 
        $f["thumbnail"] = "<a href=\"".urldecode($f["link"])."\" target=\"_blank\"><img src=\"".$PHP_SELF."?thumbnail=".urlencode($path.$f["name"])."\" style=\"text-align: left;\" alt=\"\"/></a>"; 
    }

David448

It would solve my problem, that's what would happen.

I must bow to you now 😃

Just when I think I'm getting the hang of code, I strugle with something like this and one of you guys solve it in minutes. :p

Thanks.