Unexpected {

homer09001

im tryingto write an iff sttement to check to see if a value is = to or > than a certain value when it is it displays different text but it keeps saying there is an un expected { on line

here my code anway

<h4>Below is a list off all Members</h4>

<body bgcolor="#CCCCCC" text="#000000" link="#000000" vlink="#000000" alink="#000000">

<?php


// Database viewer script for GEA
// (C) Hurst Un-Limited, James Francis Douglas Hurst 2005. All rights reserved.

$server = "localhost";
$username = "*****";
$password = "******";
$pilot_db = "******";

// Open MySQL connection
$mysql = mysql_connect($server,$username,$password);
mysql_select_db($pilot_db,$mysql);

// Get data from table
$result = mysql_query("SELECT * FROM pilotinfo WHERE visible='1'",$mysql);
while($row = mysql_fetch_array($result)) {
	$data[] = $row;
	}

// Set up the table, put little bits of HTML after the ? > if you want if you want.
?>

<table border=1 cellpadding=2 cellspacing=0><tr><th width="48">ID</th><th>Name</th><th>Flight Hours</th><th>Rank</th></tr>

<?php

// Begin printing data
for($i=0;$i<count($data);$i++) {
	$temp1 = $data[$i]['id'];
	$temp2 = $data[$i]['name'];
	$temp3 = $data[$i]['hour'];
	print("<tr><td>EZY- $temp1</td><td>$temp2</td><td>$temp3</td></tr>");
	}

########################
#below is the concerning if statment#
########################
if ($temp3 = "0")
{
$val = "0";
$rank = "rank 1";
}
else ($temp3 = "121")
{#<----------------- theres the apparent unexpected {
$val = "121";
$rank = "rank 2";

echo "<td>$val</td>";

print("</table>");

// Add thats all folks!
?>

devinemke

homer09001 wrote:
// Add thats all folks!

no it's not folks! you forgot the closing } in your else statement.

homer09001

i just realised that but the problem is i want it to check to see if $temp3 => 0 if it is then display text 'rank 1' if its is => 121 siaply text 'rank 2' see what i mean i just cant get it to do it right if i put

$temp3 ==> 0

it comes up with

Parse error: parse error, unexpected '>' in /home/homer090/public_html/easyjetv/roster.php on line 40

same if i do a less than <

scandog

from what I can see from your code you don't close your else statement with a }

If you have more than one line that you want to have the else statement do then you have to have it in between {}

example

if ($temp == 0)
{
    do this
}
else
{
    do this
}

Hope that helps

homer09001

ok sorted problem now

new prolbme though there are 2 members in teh table the if statement only works on teh second members rank column not the first look :http://www.danhill.frihost.net/easyjetv/index.php?option=com_content&task=view&id=12&Itemid=38

heres the bit of code

<?php

// Begin printing data
for($i=0;$i<count($data);$i++) {
	$temp1 = $data[$i]['id'];
	$temp2 = $data[$i]['name'];
	$temp3 = $data[$i]['hour'];
	print("<tr><td>EZY- $temp1</td><td>$temp2</td><td>$temp3</td>");
}	
if ($temp3 == 0)
{
$val = "0";
$rank = "rank 1";
} 
elseif ($temp3 == 121)
{
$val = "121";
$rank = "rank 2";
}
echo "<td>$rank</td></tr>";
print("</table>");

maxpup979

that is because the if is outside of the loop. you are only testing on the last value of temp3.

homer09001

ok where do i put the If statement then?

Weedpacket

Inside the loop?