problem with IF Statment

[homer09001]

heres my code

<?php
if ($temp3 == 0)
{
$val = "0";
$rank = "rank 1";
} 
else {
$val = "121";
$rank = "rank 2";
}
$temp4 = "$rank";

// Begin printing data
for($i=0;$i<count($data);$i++) {
	$temp1 = $data[$i]['id'];
	$temp2 = $data[$i]['name'];
	$temp3 = $data[$i]['hour'];
print ("<tr><td>EZY- $temp1</td><td>$temp2</td><td>$temp3</td><td>$temp4</td>");
}	

print("</table>");

?>

what im trying to do is get it so that when they php gets the info from the database it check the value of $temp3 which is the amount of hours someone has on their record and if its = or > 0 the text "rank 1" is displayed inteh 4th column of the table ie got on the page and when $temp4 = or > 121 the text "rank 2" is displayed int eh 4th colum but for some reason its assigning rank 1 to all the records can someon etll me where ive gone wrong bearing in ind im not very good with php im taching myself

and yes i have 2 records and yes the 2nd record is = to 121 hours so it should display as rank 2 not rank 1

[sneakyimp]

your IF statement that checks on the value of $temp3 is being called before you have even assigned $temp3 a value in your loop. the if statement should come after you have assigned a value to $temp3.

php doesn't read the future.

[homer09001]

yeah im teaching my self here after about an hour of moving the if statment around i realised after i put it after $temp3 had been assigned it Worked thanks anyway