Evaluate $_POST dynamic variable

LGD

Hi guys,

There are three variables being POSTED by my form: id_a, id_b and id_c
I only want to insert in the database one of this variables so I'm dynamically setting it with $idtypevar
My question is: how can I display the value of the variable name set by $idtypevar?
Thanks.

$idtypevar = 'id_' . $_POST['tipo'];
echo $_POST[$$idtypevar];

This does not work.

laserlight

echo $_POST['id_' . $_POST['tipo']];

LGD

That doesn't work either...

devinemke

I only want to insert in the database one of this variables...

i don't quite understand the question. which variable do you want to use?

LGD

The one resulting from this line of code

$idtypevar = 'id_' . $_POST['tipo'];

which can be: id_a, id_b or id_c

laserlight

That doesn't work either...

That implies that your implementation is wrong.

Try this script:

<?php
if (isset($_GET['tipo'])) {
	if (isset($_GET['id_' . $_GET['tipo']])) {
		echo $_GET['id_' . $_GET['tipo']];
	}
}
?>

An example query string would be ?tipo=a&id_a=test

LGD

laserlight wrote:
echo $_POST['id_' . $_POST['tipo']];

Sorry, my mistake. This does work. I was updating my code in the wrong line. :rolleyes: