if ($x == 1 or $x == 2 or $x == 3) how to write this?

listenmirndt

thanks

-Arron

deep

if($x == 1 || $x == 2 || $x == 3)

toplay

Since it's a sequential integer value, you can do this too:

if ($x > 0 && $x < 4) {
}

FYI: http://us2.php.net/operators.comparison

discostudio

deep wrote:
if($x == 1 || $x == 2 || $x == 3)

if($X == 1 || 2 || 3)

works also

toplay

discostudio wrote:
or

if($X == 1 || 2 || 3)

works also

No, in PHP this is absolutely wrong!

<?PHP

$x = 4;

if($x == 1 || 2 || 3) {
    echo "In here and value is: $x"; // displays: In here and value is: 4
}

?>

discostudio

Why wouldn't the

if($X == 1 || 2 || 3)

option work.

I have used it on many occasions and have never found a bug.

toplay

discostudio wrote:
Why wouldn't the

if($X == 1 || 2 || 3)

option work.

I have used it on many occasions and have never found a bug.

I'm sorry to say that you have not tested your code very well and you have bugs in your code. Go back and fix them.

The "|| 2" and "|| 3" parts in the example "if" statement provided by you will always evaluate to TRUE. Meaning the code within the "if" statement will always get executed regardless of the value of the $X variable.

If you had this for example:

if ($X == 1 || 0) {
}

The zero evaluates to FALSE, so in this case the code within the "if" statement will only be executed when the $X variable is equal to one. Not even if $X contained a zero value.

Run some of these test code to see for yourself.

🙂

discostudio

No, I comletely believe you, I will go and sort it out. Cheers

Weedpacket

You could also write it as

if ($x == 1 or $x == 2 or $x == 3)