PHP generated list problem.

CaptainK

Hi there,

Heres the code:

function displayInfoCat(){

//Display example menu items.

 $ID = $_GET['cat'];
 if($ID == ""){
 $ID = 1;
 }
 $cat = getInfoCat($ID);
 foreach ($cat as $row){
 echo '<li><a href="index.php?cat=' . $ID . '&example=' . $row['ID'] . '">' . $row['title'] . '</a></li>';
 }
}

Now the problem is I would always like to have 5 list items but sometimes there are only 3 results from the database.

Hope you get what I mean. Its hard to explain.

Any help much appreciated.

planetsim

So what exactly is the problem, perhaps try re-thinking what the problem is then re-ask.

CaptainK

Ok. So the list looks like buttons on the site and for consistency I would always like 5 buttons to be displayed even if there is no content to go in them. Fillers if you like.

I would like to create a loop which reiterates 5 times even if there are no more results in the array.

planetsim

Why not use for instead of foreach e.g.

// im assuming $cat is of $cat[0]['varname'];
function displayInfoCat()
{

//Display example menu items.

$ID = $_GET['cat'];
if($ID == "")
    $ID = 1;

$cat = getInfoCat($ID);
for ($i = 0; $i < 5; $i++)
{
    if (isset($cat[$i]) && is_array($cat[$i]))
        echo '<li><a href="index.php?cat=' . $ID . '&amp;example=' . $cat[$i]['ID'] . '">' . $cat[$i]['title'] . '</a></li>';
    else
        echo '<li></li>'; //empty bullets
}
}

CaptainK

Thats great. Thanks.

I was nearly there just had my array values confused.