working with parameters in url string

Tonka1979

I don't know if this is a specific php issue, but it happened that it occured to me within a site made of php pages. We have the following link:

http://www.rambuzau.ro/main.php (please check it)

Whenever I click on various buttons in the top bar, I get to the same "main.php" page but with different parameters like this: "main.php?pag=1", "main.php?pag=2" and so on.

How is this happening? Where is the code that makes it possible for the viewer to see various data embeded in the same main.php page depending on the "pag" parameter value? It's not in the code displayed by right-click->View Source...

This is probably a begginer's problem (like I am), but can anyone explain to me the mechanism? Thanks, guys! Quick answers appreciated.

Tonka1979

I don't know if this is a specific php issue, but it happened that it occured to me within a site made of php pages. We have the following link:

http://www.rambuzau.ro/main.php (please check it)

Whenever I click on various buttons in the top bar, I get to the same "main.php" page but with different values for "pag" parameter like this: "main.php?pag=1", "main.php?pag=2" and so on.

This is probably a begginer's problem (like I am), but can anyone explain to me the mechanism? Thanks, guys! Quick answers appreciated.

Tonka1979

I don't know if this is a specific php issue, but it happened that it occured to me within a site made of php pages. We have the following link:

http://www.rambuzau.ro/main.php (please check it)

Whenever I click on various buttons in the top bar, I get to the same "main.php" page but with different parameters values for "pag" like this: "main.php?pag=1", "main.php?pag=2" and so on.

This is probably a begginer's problem (like I am), but can anyone explain to me the mechanism? Thanks, guys! Quick answers appreciated.

subwayman

Yes it is. The code is in the pafe served. Right Click¦veiws source and you will find

<td class=tdmenu2 onMouseOver="do_menu_on(this)" onMouseOut="do_menu_off(this)" onClick="do_menu_open('main.php?pag=1')">DESPRE NOI</td>

Of course you will need to check out the script for do_menu_open() as well.

Tonka1979

Thanks! I've already seen this line and the function "do_menu_open" code which simply opens a page:

function do_menu_open(pbj)
{
window.location=pbj;
}
It simply directs you to "main.php" with value 1/2.. for the "pag" parameter when you click on a button by sending the value of the parameter.

But my question was reffering to something else: what segment of code actaully GETS the value of the parameter and displays main.php with different data deppending on parameter value?

toxic_brain

in main.php u have to check like,

 
 $page=$_GET['pag'] ;  

switch ($page)  { 
 case 1:      $file = first.php'  ;   

 break ;    case 2:     

 $file = 'second.php'  ;   

 break ;  
---  -
--  

}   

include ($file);

Tonka1979

Thanx!

Firt of all, I can't check main.php, I can olny take a look in View Source. And I suppose the code you wrote is php server-side and this is why it is not shown when you choose View source, right?

Second, the sample you wrote actually means that there are a few pages (firts.php, second.php etc.) but in my case (and a lot of others, take a look at this site for example) there is only one page (main.php) which is repeteadly displayed but with different values for the parameter "pag". How does this happen? main.php has the same look&feel from one value of "pag" to another, only the data in the middle area changes.

toxic_brain

ofcos..
server put the whole code written in first.php into main.php while u call include. every time u view source of main.php it will have the content of the included file..

Tonka1979

I see.. by calling that "include"...

Thanks a lot, see ya!

Tonka1979

One other thing: do you happen to have a sample php site with such a server-side code segment?
To actually see it at work...
If yes, you can send it at cosminp79@yahoo.com, thanks!

vaaaska

Yes, it is in the code...

Your script is outputting it - plain and simple.

If you want specific help you'll need to post your code. But what is the point to your question?

Weedpacket

main.php would use the value it finds in $_GET['pag']
http://www.php.net/manual/en/language.variables.external.php

Unless you're talking about the Javascript, in which case it's not a PHP issue.

Tonka1979

It's php and I suppose the code segment test for the value of "pag" and displays the same main.php page only with different data put there by including different files. Thanks!

Tonka1979

No, it's not in the code displayed with View source.. there you have only the value of "pag" parameter sent to some server-side code which is the one I was interested in (the code that actually GETS (through $_GET["pag"] ) the parameter value and tests against 1,2... . However, issue is solved, check the same thread in "General Help" Section. Thanks!

vaaaska

Ok, so this is meaningless then...

<table cellpadding="1" cellspacing="0" width="760" height="24" background="img/baragri.gif"><tr><td valign="top" align="center">
<table class=tmenu cellspacing="0" cellpadding="3"><tr>
<td class=tdmenu2 onMouseOver="do_menu_on(this)" onMouseOut="do_menu_off(this)" onClick="do_menu_open('main.php?pag=1')">DESPRE NOI</td>
<td class=tdmenu1 onMouseOver="do_menu_on(this)" onMouseOut="do_menu_off(this)" onClick="do_menu_open('main.php?pag=2')">CONSUMATORI</td>
<td class=tdmenu1 onMouseOver="do_menu_on(this)" onMouseOut="do_menu_off(this)" onClick="do_menu_open('main.php?pag=3')">DEZVOLTARE</td>
<td class=tdmenu1 onMouseOver="do_menu_on(this)" onMouseOut="do_menu_off(this)" onClick="do_menu_open('main.php?pag=4')">MEDIA</td>
<td class=tdmenu1 onMouseOver="do_menu_on(this)" onMouseOut="do_menu_off(this)" onClick="do_menu_open('main.php?pag=5')">EDUCATIE</td>
</tr></table>
</td></tr></table>

Tonka1979

It was useless for my purpose; the "do_menu_open" function is not even php, it's javascript.

crashingwaves38

I think she was more asking for an explanation of exactly how parameters are passed to a url string--being a newbie myself, this is something I don't have a grasp on yet either.

My particular problem in this area is such: I'm creating a photo album that prints the thumbnail and the date into a cell in a 3x5 table. I have the table (somewhat) down. However, I want to have the picture link to a popup that includes the full-sized picture and all of the other information linked to that particular picture. What I currently have is this:

echo '<td>';
echo "<img src=".$a_row['url']." width=86 height=64 border=0> ".$a_row['dateofpic'];
echo '</td>';

I assume what I need to do the popup is something more like this:

echo '<td>';
echo "<a href=\"$PHP_SELF?picid=$a_row['id']\" target=_blank><img src=".$a_row['url']." width=86 height=64 border=0></a>br />".$a_row['dateofpic']";
echo '</td>';

My problem is that I then need to use that popuped window to pull information from the database. I know how to do the MySQL query--what I need to know is how to make the actual page hold the query.

I hope I've explained it sufficiently--if I haven't, I'll try again. laughs