Simple question, best described with code....
<?php
function steve ($input, 'message');
echo $message . $input;
}
function dave ($var1) {
$steve = bob ($var1, 'hello');
return $steve
}
?>
This is all made up for this example, but basically, 'bob' is another function which is being called from within the function 'dave' and obviously, when I try to run this I get the old "call to undefined function" error.
How do I get around this one?
Thanks
jonny.