preg_replace pattern help

[KashKurcura]

hello:

i am doing a preg_replace and my pattern is

$pattern = '/#(\d+)/i';

this will find the number after the # sign, but how do i tweak this to find this 051007-1416-WNM7L4RV-9765 after then number sign?

thanks

[Kudose]

$regex = '%^{#([0-9]{6}-[0-9]{4}-[A-Z0-9]{8}-[0-9]{4})$%';}

The above regex will match the pattern above, so long as the format is the same across the board...

$regex = '%^{#([-A-Z0-9a-z]+)$%';}

The second regex (above) will match as well, but is not as strict.

Hope that helps.

*EDIT*
Added backreference support to regex...