menu link

sirTemplar

hi. i have page with a table with two columns. the left side column contains the menu. the right side should contain the contents of the links on the menu, like when they click link 1 on the menu i want it to appear on the right table. how do i do this with php? thanks

subwayman

You should move this to a javascript forum as it requires client side functionality and php is serverside.

void_function

No necessity to use javascript here. The PHP page can format content according to the link clicked:

left column html:

<?php show_menu(); ?>

right column html:

<?php show_contents($page_id); ?>

Have your menu links be formatted as:

page.php?id=1
page.php?id=2
etc... no need for numeric id's, though.

Then, at the beginning of page.php fetch the ID:

if (isset($GET['id'])) $page= (int) $GET['id']; else $page=0;

Note the (int) -- have it only if you use numeric page definitions. Then in the show_contents($page) function you decide the content according to the ID value passed through links.

This way on each click you reload entire page and no need to use (i)frames.

Hope this helps.

sirTemplar

i get this error!

Fatal error: Call to undefined function: show_contents()

mmonaco

... you need to write it.

But instead just use a switch. Create a function for each page you'll want. page_1(), page_2(), etc... then in the righthand cell include this:

switch($_GET['id']) {
   case 1:
      page_1();
      break;
   case 2:
      page_2();
      break;
   default:
      page_default();
      break;
}

The break statements are necessary, the default case should come last, each of those page functions will display whatever you'd like them too, the $_GET['id'] comes from the ?id=# following the URL in the link.

If you'd like to use string identifiers instead of numbers, they need to be in quotes in the switch:

 case "contacts":
      page_contacts();
      break;

sirTemplar

here is part of my code:

mainpage.php - this is the page that is loaded with the table with left and right cell. the menu01.php that is included is where i have the menu links and it is displayed on the left cell....

<table border="1" cellpadding="5" cellspacing="0" style="border-collapse: collapse" bordercolor="#FFFFFF" width="100%">
  <tr>
    <td width="27%"><?include ("menu01.php");?></td>
    <td width="73%">
	<?php 
	switch ($_GET['link']) { 
    case 1: 
    echo 'link=page01'; 
    break; 

case 2: 
echo 'link=page02'; 
break; 

case 3: 
echo 'link=page03; 
break; 

default: 
echo 'choose from left menu item'; 
break; 
} 
?>
</td>
  </tr>
</table>

menu01.php looks like this. the linked page are the pages i want to display on the right cell.

<a href="mainpage.php?link=page01.php">Page 1</a><br>
<a href="mainpage.php?link=page02.php">Page 2</a><br>
<a href="mainpage.php?link=page03.php">Page 3</a><br>

what am i doing wrong and/or missing? thanks for the time to help...

subwayman

Your swi tch statement is not using the values you set in your link.

means clicking this link will result in link being set to 'page01.php'.

You switch statement checks for values 1, 2 and 3