text in new array ??

Snake_PHP

hello,

I'm in problem see this codes

$SQL = "select * from setting ";
$Result = mysql_query($SQL);
$getinfo = mysql_fetch_array($Result);

$ext_file = $getinfo["types"];


// var ($ext_file) == gif,jpg,png,zip

$Ext = array($ext_file);

if(in_array("rar",$Ext)){

ECHO " I Found ";
}else{
ECHO " Not Found";
}


echo "1 :".$Ext[0]." 2 :".$Ext[1];

but $Ext[1] NULL 😕 and $Ext[1] = "gif,jpg,png,zip" All :bemused:


$r = explode(",",$ext_file);
$c = count($r);

echo $c; // 6

help me ...

Weedpacket

If I understand your problem (and it's so badly written I may not have), then you're storing a bunch of file extensions in a database field as a comma-separated list, and then you want to search to see if a particular extension is in that field (there's a design flaw right there).

Haven't a clue why you've got the third code snippet, because that would appear to be the answer; explode the returned field to get an array that you can use in_array() on.

Snake_PHP

the answer

<?
$ext = "gif,rar,zip";
$extd = "png";
if( $ext != '' && !in_array ( $extd, explode ( ',', $ext ) ) )
{
$msg = " Not Found :( ";
}else{
$msg = " Found :) ";
}

echo $msg;
?>

thanks for help 🙂