[RESOLVED] Passing the last value of $i?

[pettsogn]

Hi!

I wonder how i can pass the the number of results from this loop:

$a = 0;
$a1 = 0;
$res4 = mysql_query("SELECT * FROM table ORDER BY id DESC LIMIT ".($a).",100",$db);
if($info4 = mysql_fetch_array($res4)) {
$i = $a1;
if ($i>0)$i--;
do {
    $i++;
	$dyr[$i] = $info4["navn"];
}
while ($info4 = mysql_fetch_array($res4));
}

to this function:

for ( $i = 0; $i< $number_of_results; $i++) {
	echo "$dyr[$i]<br>";
}

thanks!

[tunage]

$number_of_results = count($info4);

[pettsogn]

thanks 🙂

worked when i changed

count($res4);

to

count($dyr)+1;