Retain the local file path.

[joe2]

Hi,

There is form with image upload. On error local file path becomes empty in file upload field. Is there any way to retain local file path in the file upload field. If some field in the form is empty. I am using server side validation of the form. So, on error form reload with error message.

Thanks in advance.

[batman]

when you set your error message instead of using an include or a header to a certain page use something like this:

if($validation == "false")
{
echo "I'm sorry there was an error!";
header("Location: javascript:history.go(-1)");
exit();
}
else
{
//finish upload here!!
}

script is saying if error happens then print message, go back, and stop the script. Otherwise continue on uploading!! 😛

[joe2]

Thanks for the reply.

It is one page. Bith form and process is on one page.So, there is no question of redirect.

[thinfile]

Not too sure If I have understood you correctly; but if the form post does not contain file information that could be either because the upload was too large to handle with your PHP configuration or the user didn't select a file.

One easy way is to use javascript to validate the file selection box is filled.

--
Thin Image Upload
Image upload with client side resize and filtering.

[batman]

Did you try what i gave you? The code doesnt redirect anywhere except 1 step backwards just as if the user hit the back button except this would do it automatically. Doesn't matter if it only one page....

[batman]

Im not sure how your code is though you may not be able to send headers. So if you dont mind making a clickable link then replace the headers(); with

echo "<a href=\"javascript:history.go(-1);\">Back</a>";

You could also try sending the value in the URL then using the $_GET method and using the get method for the default value of the field.... 😛

[joe2]

There is no problem with image upload. My scripts are uploading the image smoothly.

Suppose there are two fields one is student_name, second one is student_image. User selects image. File field filled with image path e.g. c:\mypic.gif . But user did not enter the student_name field. server side validation reloads the form with error about the student_name field. At the same time it clears file field (i.e. c:\mypic.gif). User will have to reselect the image. Is there any way that file field remain fillled with the image path (i.e. c:\mypic.gif) in the case of error.

Thanks

[Weedpacket]

Not really; for the same reason why you can't put a value in by default in the first place. Consider adding some Javascript to check whether fields are empty or not. You'll still need to check server-side, but at least people who have Javascript running won't have their file form fields cleared if they leave their name field blank.

[bretticus]

I have certainly looked for this in the past and it seems I couldn't hack it out. So I went searching and found something similar to this explanation

[joe2]

Thanks bretticus and weedpacket. In nuttshell, it is not advisable or to some extent not possible.

[batman]

You could also try sending the value in the URL then using the $_GET method and using the get method for the default value of the field.... 😛

Like I said. Obviously if your doing a check on the fields they both have names.

<?
$var = $_POST['imagevalue']; //or whatever you named it
$var2 = $_POST['name'];
//do your validation here
if((!$var) || (!$var2)){
	echo 'You did not submit the following required information! <br />';
	if(!$var){
		echo "Please set a value for var1.<br />";
$name = "$var2";
	}
	if(!$var2){
		echo "Please set a value for var2.<br />";
$default = "$var";
	}
	}

Then for the input where they type the path use something like:

<input type="text" name="name" value="<? if(isset($name)){echo"$name";}else{echo"";} ?>">

<input type="text" name="image" value="<? if(isset($default)){echo"$default";}else{echo"";} ?>">

[joe2]

<?
$var = $_POST['imagevalue']; //or whatever you named it
$var2 = $_POST['name'];
//do your validation here
if((!$var) || (!$var2)){
    echo 'You did not submit the following required information! <br />';
    if(!$var){
        echo "Please set a value for var1.<br />";
$name = "$var2";
    }
    if(!$var2){
        echo "Please set a value for var2.<br />";
$default = "$var";
    }
    } 
  ?> 
  <form method="POST" action="post.php">
 <input type="text" name="name" value="<? if(isset($name)){echo"$name";}else{echo"";} ?>"><br><br>
<input type="file" name="imagevalue" value="<? if(isset($imagevalue)){echo"$imagevalue";}else{echo"";} ?>"><br><br> 
<input type="submit" value="ok" name="submit">
</form>
 

i tried this , but it is not working.

[batman]

ummm...did you modify it for your own code? Also did you use the second part and modify that also??

<input type="text" name="name" value="<? if(isset($name)){echo"$name";}else{echo"";} ?>">

If you did then post what you changed and how your trying to get it into your own code. Post some of your own code....(your form page where the input is located). 😛

[joe2]

yes i have modified the code. Since i need the inout type file (you can see i the code). So one of the field i converted to file.

your code is working perfectly alright with the input type text.

Thanks

[batman]

im confused....so are you set now or u still need more??