[Q] Path problem in PHP when using include()...

cyanblue

Howdy... 🙂

I have this test file...
http://localhost/dev/PHP/includeTest/includeTest.php
which includes this file...
http://localhost/dev/PHP/includeTest/Directory1/Directory2/test.php

<?php
	include("Directory1/Directory2/test.php");
?>

<img src="Flash.jpg" />

When I view test.php alone, it reads Flash.jpg file just fine, but if I view includeTest.php, I do not get that image file... Obviously the test.phpis looking for the Flash.jpg from this location http://localhost/dev/PHP/includeTest/Flash.jpg instead of http://localhost/dev/PHP/includeTest/Directory1/Directory2/Flash.jpg since the base directory has changed...

So, what is the best way to get away with this problem??? I sure don't want to move all the JPEG files into the root directory, http://localhost/dev/PHP/includeTest in this case, and I am trying to figure out to see if there is any way solve this problem...

Thank you... 🙂

toxic_brain

u have 2 options.

1.
specify the path in dev/PHP/includeTest/Directory1/Directory2/test.php as

Directory1/Directory2/Flash.jpg

2.
use absolute path

cyanblue

For now, I am doing this...

<?php 
    // includeTest.php
    $path = "Directory1/Directory2/";
    include($path . "test.php"); 
?>

// test.php
<img src=$path . "Flash.jpg" />

This works for a certain extend... I don't really like this idea much though because the base path for the test.php becomes the directory of the includeTest.php...
So, what happens is that the Flash movie that's sitting in $path is looking the images to load(gallery sort of app) from the includeTest.php directory which does not exist in there... 🙁