dynamic button creation -- code problem

[cjung1021]

I am making the scripts can create button dynamically. It creates the several submit buttons but I can not line up the created button. Once one button is created, the second button is created in next line not in the same line. I don't know how to figure it out now. Please give me your idea. Here is my code.

<?
$button = array();

$button[0] = 'hello';
$button[1] = 'welcome';
$button[2] = 'good-bye';

display_toolbar($button);

function display_button($button)
{
$url = "action.php?action=$button";
echo "<form action=$url method=POST>";
echo "".create_button($button)."";
echo "</form>";
}

function create_button($button)
{
$a = "<input type=submit value=$button>";
return $a;
}

function display_toolbar($button)
{
$j = count($button);
$i=0;
while($i < $j)
{
if($button[$i])
{
display_button($button[$i]);
}

$i++;
}
}

?>

Thanks.... 😕

[_theworks]

its because there all in there OWN form wen they should all be in ONE form....

[BobLennon]

_theworks wrote:

its because there all in there OWN form wen they should all be in ONE form....

Could you please explain what this reply means?

Thanks...Bob Lennon

[_theworks]

hey, sorry i guess that was kind've vague 😃

ok think of it like this....

/// these buttons are all in one form.
<form>
  <input type="submit" value="menu button 1!">
  <input type="submit" value="menu button 2!">
  <input type="submit" value="menu button 3!">
</form>

//// these buttons all have there own form

<form>
  <input type="submit" value="menu button 1!">
</form>
<form>
  <input type="submit" value="menu button 2!">
</form>
<form>
  <input type="submit" value="menu button 3!">
</form>

so you want all the buttons in there own form as aposed to each button having its own form 😉

[cjung1021]

Thank you for your advice. It is helpful... I got the solution... Thanks again :p