Form Method / passing parameters

imjackdorson

A very simple question i suppose:

I have muliple submit buttons (say 5) in my php code & they're all in a form. Now should I have 5 different form methods [<FORM METHOD="POST" ACTION="view.php" name="formname">] and index to 5 different code files(eg view.php,view1.php,view2.php,etc) or is there a way to pay on a parameter to the view.php , then do its specific task?

<html>

<FORM METHOD="POST" ACTION="view.php" name="formname">
Search function

<table border="0" cellspacing="3" cellpadding="3">
<tr>
<th><font face="Arial, Helvetica, sans-serif">REDBOX</font></th>
<TD><INPUT TYPE="submit"></TD>
</tr>
<th><font face="Arial, Helvetica, sans-serif">Click here for Green Box</font></th>
<TD><INPUT TYPE="submit" value='Submit Button'></TD>
</tr>

<TABLE width="90%" border="2">
<TR bgcolor="green">
	<TD>Item1</TD>
	<TD>Item2</TD>
	<TD>Feedback</TD>
</TR>

$query ="select * from box";

$result = mysql_query($query);

?>
<?
while($data = mysql_fetch_array($result,MYSQL_BOTH))
{

<TR>
	<TD><?echo $data[0];?></TD>
	<TD><?echo $data[1];?></TD>
	<TD><?echo $data[2];?></TD>
	<TD><?echo $data[3];?></TD>
	<TD><INPUT TYPE="submit"></TD>
</TR>

<?
}
?>
<?
mysql_free_result($result);
mysql_close();
?>

</TABLE>

</FORM>
</BODY>
</HTML>

devinemke

you can have as many submit buttons in a single form as you want:

<?php
if (!isset($_POST['submit']))
{
	echo ' 
	<form action="" method="POST">
	<input type="submit" name="submit" value="1">
	<input type="submit" name="submit" value="2">
	<input type="submit" name="submit" value="3">
	<input type="submit" name="submit" value="4">
	<input type="submit" name="submit" value="5">
	</form>
	';
} 
else 
{ 
	echo 'you pressed ' . $_POST['submit'];
}
?>