Problem with mysql_fetch_array ( $vabiable[$variable] )

[kumschick]

Hi,

I want to create a Multilingualmenu and I have a problem with a variable
I know that I can't use a $vabiable in a $variable

-> $row[content_$lang]

But how could I do this

if(empty($lang) {
  $lang="eng";
}

$get_menu=mysql_query("select * from $menu where status='1'");
while($row=mysql_fetch_array($get_menu))
  {

echo"<a href=\"$row[link]\">$row[content_$lang]</a><br>";

  }

[rincewind456]

Change

echo"<a href=\"$row[link]\">$row[content_$lang]</a><br>";

to

echo '<a href="'.$row['link'].'">'.$row['content_'.$lang].'</a><br />'; 

[Installer]

This will actually work, and as a bonus won't produce an error message:

echo '<a href="' . $row['link'] . '">' . $row['content_' . $lang] . '</a><br />';

[kumschick]

thx second works!