[RESOLVED] Variable for filename

[KnightWolfJK]

n00b question, but I've searched and can't find the answer.

I need to echo the filename of the PHP page that is currently in use via a template. For example, on index.php, the variable would return 'index,' and on /folder1/folder2/whatever.php the variable would return 'whatever.'

It seems like basename() would do the trick, but that still requires specification of the path, which I'd like to avoid.

Any suggestions? Thanks

[mattotto77]

This should guide in the right path

$variable_name=getenv("HTTP_REFERER");

[Rodney_H_]

I think basename is what you are looking for. Have you tried to use it?

It does not require you to know the current path information of the file currently employed, if that is what you are thinking. Rather, it returns the current file name component of the path, just as you are seeking to do...

[KnightWolfJK]

mattotto77: I couldn't get $variable_name=getenv("HTTP_REFERER"); to return any data, but it started me in the right direction. Thanks. I'm using $variable=($_SERVER['PHP_SELF']); but it returns the full path (/folder1/folder2/file.php). If I could limit the output to just file I'd be set.

Rodney: When I use basename() I'm using the following:

<?php
$path = "/home/httpd/html/index.php";
$file = basename("$path", ".php");
?>

As far as I can tell, it's purely dependent on having the path determined. I tried taking out the path and it returns nothing. Am I missing something?

[Rodney_H_]

OOps. No, I guess I screwed up. Sorry.

This may work for you, but seems to be the long way around the mountain...

<?php
function getFile(){
	$pos = strpos($_SERVER['PHP_SELF'], '/');

if($pos !== false)
{
	$parts = explode('/', $_SERVER['PHP_SELF']);
	$count = count($parts);
	$variable = substr($parts[$count-1], 0, -4);
}
else {
	$variable = substr($parts[$count-1], 0, -4);
}
return $variable;
}

echo getFile();
?>

[KnightWolfJK]

Bah... Okay, the function works great. But when I dump it into this:

<?php 
include("/absolute/path/to/script.php");
$visitors = daily_count("$getFile().log",""); //with or without the $
echo " ".$visitors[0]." visitor(s) today and  ".$visitors[1]." visitors since ".$visitors[2]
;?>

it creates a filename of getFile().log. I realize now that it's already inside of another echo command and that I need a variable. It seems totally obvious that I should be able to assign the results of the function to a variable that I can use, but I can't seem to find it. I've looked here and here and some other places.

[Rodney_H_]

Maybe this will help, by adding the ".log" extension in the function and creating a global variable out of the logFile:

<?php
// create function
function getFile(){

global $logFile;

$pos = strpos($_SERVER['PHP_SELF'], '/');

if($pos !== false)
{
    $parts = explode('/', $_SERVER['PHP_SELF']);
    $count = count($parts);
    $logFile = substr($parts[$count-1], 0, -4) . 'log';
}
else {
    $logFile = substr($parts[$count-1], 0, -4) . 'log';
}

return $logFile;
}

// call function
getFile();

include('/absolute/path/to/script.php');

$visitors = daily_count($logFile,"");

echo $visitors[0] . " visitor(s) today and  ";
echo $visitors[1] . " visitors since "  . $visitors[2];

?>

[KnightWolfJK]

Awesome. It was making it a global that I was missing- thanks a ton.
I ended up going with:

<?php
// create function
function getFile(){
    global $logFile;
    $pos = strpos($_SERVER['PHP_SELF'], '/');
    if($pos !== false)
    {
        $parts = explode('/', $_SERVER['PHP_SELF']);
        $count = count($parts);
        $logFile = substr($parts[$count-1], 0, -4);
    }
    else {
        $logFile = substr($parts[$count-1], 0, -4);
    }
    return $logFile;
}

// call function
getFile();
include('/absolute/path/to/script.php');
$visitors = daily_count("$logFile.log","");
echo $visitors[0] . " visitor(s) today and  ";
echo $visitors[1] . " visitors since "  . $visitors[2];
?>

to maintain the ability of changing the file extension without editing the function. Thanks again.

[Rodney_H_]

Cool. glad that worked.

Regards for a happy new year.