Selecting biggest file....

[Thunder]

Hello, Im fairly new to php. I have 10 images that are uploaded. I would like to select the largest one (the one with the biggest file size). The only way I have come up with to do this is an if-elseif thats rather long and I bet hardly efficent. Is there a better way to do this? Thanks
John

[Thunder]

Hmm I got to thinking and what about an array. If I add all the filenames to an array, and then loop through the array, perform a filesize() on them and check if its then store the greatest in a var, and just compare that each try. Lemme code this out...Still doesnt seem to effiecient though.

[bpat1434]

How about reading the directory, and getting the file-size during the reading?

<?php

$dir = 'directory/to/be/scanned/'; // Note the ending "/"

$d = dir($dir);
while(false !== ($entry = $d->read()))
{
  if($entry != '.' && $entry != '..')
  {
    if(is_file($dir.$entry))
    {
      $files[$entry] = filesize($dir.$entry);
    }
  }
}

asort($files, SORT_NUMERIC);

$largest = key(end($files));
?>

$largest should have the filename of the largest file now.

~Brett

[Thunder]

Thanks, That code is a whole lot cleaner than what I came up with. The only issue in it I had was the end() and key(), I had to break it out so that is became

asort($files, SORT_NUMERIC);
end($files);
$largest = key($files);

Thanks again for the awesome code.

John

[bpat1434]

No problem.

~Brett