[RESOLVED] Static functions in php 4?

[ugasucks]

I am forced to use PHP 4 due to hosting problems, thus any OOP advancements from php 5 are not applicable here...

My real point of this question is, 'Can you create static functions in PHP 4?".

Say I have a class named Foobar and this class has a method called getMatchingFoobars, which returns an array of Foobars that match a database query (called param here). I've used this pattern extensively in Java, but I can't seem to apply it to PHP 4.

What I'd really like to do is something along these lines:

$matchingFoobars = Foobar->getMatchingFoobars(params);

or

$matchingFoobars = new Foobar()->getMatchingFoobars(params);

but instead it seems like I have to do the following:

$aFoobar = new Foobar;
$matchingFoobars = $aFoobar->getMatchingFoobars(params);

Am I missing something?

Thanks

[bpat1434]

class FooBar
{
  var $params;

  function connect_db($db)
  {
    $con = mysql_connect('localhost', 'user', 'pass');
    mysql_select_db($db, $con);
    return $con;
  }

  function queryFoobar($query)
  {
    $conn = $this->connect_db('database');
    $result = mysql_query($query);
    return $result;
  }

  function mkarrayFoobars()
  {
    $result = $this->queryFoobar("SELECT * FROM `table` ORDER BY id ASC LIMIT 25");
    $i=0;
    while($row = mysql_fetch_array($result))
    {
      $this->params[$i][$row['item1']] = $row['item2'];
      $i++;
    }
  }

  function getMatchingFoobars()
  {
    $this->mkarrayFoobar();
    return $this->params;
  }
}

$aFoo =& new FooBar;
$params = $aFoo->getMatchingFoobars();

That should work. And it's PHP 4 compatible.

~Brett