Array_chunk function

[wipeskim]

Hi

Thanks Devinemke for the help i tryed to use the array_chunk function to display the photos in my database in 4 columns instead of listing one photo under other but i wasn't successfull this is how i used the code to display:

$photos=$result["photo"]; // where displays the url of the photos
$Array=array("$photos");

$rows = array_chunk($Array[0], 4);

printf("<img src='$rows'>");

it gives the following error: Warning: array_chunk() expects parameter 1 to be array, string given in /home/photos/public_html/produtos.php on line 406

How do i correct this in order to display the photos in 4 columns with this function?

Once again Thanks!

[bpat1434]

If you're gettin results from a database, why not just do this:

$i=1;
while($row = mysql_fetch_array($result))
{
  echo '<img src="'.$row['photo'].'"> ';

  if($i%4==0){ echo '<br>'; }

  $i++;
}

~Brett