Compare hour of day?

[StartAnISP]

I am trying to write some code that will basically tell me if it's between 9pm and 9am central time.

This will be part of a script that will page our techs only if it's after hours.

The code I have is below but for some reason it's not working, when I run it now which is currently 11:58 pm central, it tells me it's normal hours which is incorrect.

If I just try to detect if it's after 9pm that works, once I add the "&&" and the "< 09" it breaks.

Any idea why? 😕

$CentralDateTime = strtotime($date . '-1 hour');

$MyTime = date("H", $CentralDateTime);

//To simulate the hour for testing
//$MyTime = 05;

print "The hour now is: " . $MyTime;

if ($MyTime > 20 && $MyTime < 9) {
	print "<br>It's after hours";
	}else{
	print "<br>It's normal hours";
	}

[bradgrafelman]

Have you read your logic out loud?

if ($MyTime > 20 && $MyTime < 9) { 

How many numbers are BOTH greater than 20 AND ( && ) less than 9 at the same time? I don't know of any 😉

Try changing that to a logical OR ( || ), meaning if it's AFTER 20, or BEFORE 9 (i.e. between the two).

[StartAnISP]

I read it outloud 100 times 🙂

Just tired I guess, I will give this a shot..

Thanks!