[RESOLVED] Creating a PHP file and putting a line of code

[yoki]

Hi,

I'm trying to put lines of codes inside a created php page...Here is my portion of code:

$filename = 'DOC_Temp/Dauks_1.php';
$fp = fopen($filename, "w");

if ( $fp )
{
$string = "<?php require_once('../clsMsDocGenerator.php'); $doc = new clsMsDocGenerator(); $doc->addParagraph('this is the first paragraph'); $doc->output();?>";
$write = fputs($fp, $string);
fclose($fp);
header("location😃OC_Temp/Dauks_1.php");
exit();
}
else
{
die( "fopen failed for $filename" ) ;
}

Now If I open up the filename Dauks_1.php, this is the result I get:

<?php require_once('../clsMsDocGenerator.php'); = new clsMsDocGenerator(); ('this is the first paragraph'); ();?>

It seems to have omitted to put the $doc-> string...

How can I make $string to include everything? Or am I doing this the wrong way ? Please help someone! :bemused:

[devinemke]

$filename = 'DOC_Temp/Dauks_1.php';
$fp = fopen($filename, 'w') or exit('fopen failed for ' . $filename);

$string = '<?php require_once("../clsMsDocGenerator.php"); $doc = new clsMsDocGenerator(); $doc->addParagraph("this is the first paragraph"); $doc->output(); ?>';
$write = fputs($fp, $string);
fclose($fp);
header('location: OC_Temp/Dauks_1.php');
exit();

[yoki]

Many many many thanks!!! 🙂 I didn't know you could do the following:

$fp = fopen($filename, 'w') or exit('fopen failed for ' . $filename);