[RESOLVED] Setting Three Values + Input Field

[obrienkev]

Hi all,

Is the below correct in setting a third value (id).

echo '<option value="'.$row['location_ID'].'"&id="'.$row['location_name'].'">'.$row['location_name'].'</option>';
echo '';

[AcousticJames]

No, what you'll want to do is something like this:

echo '<option value="'.$row['location_ID'].'">$row['location_name'].'">'.$row['location_name'].'</option>';
echo '';

That will produce HTML that looks like this:

<option value="1">Location</option>

James

[rincewind456]

Just take out the ampersand and the html will be like

<option value="1" id="Location">Location</option>

[obrienkev]

echo '<select name="ffnumber" id="ffnumber"><option value="0">Select Name</option>';
while($row = mysql_fetch_array($result))
{
 		$value = $row['FFNumber'].'-'.$row['SurName'].'-'.$row['FirstName'];
 		echo '<option value= "'.$value.'">'.$row['SurName'].' '.$row['FirstName'].'</option>';
}
echo '</select></p>';