Getting the Julian Date?

jdc44

Does anyone have a function, or know where I can find one, for returning the Julian date for a date entered. Example: I today is 01/13/2006, what would the Julian date be for that?

Many Thanks,

JohnC

bpat1434

Have you checked [man]date/man and the user notes for help? Not sure if there's one in there or not....

~Brett

edwardoit

How about the other way?
Julian Day Count to regular date?
string like 070360 which is equal to dec 26 2007...
Any solutions?

bpat1434

I beg to differ..... Julian dates are formed by the number of days from January 1, 4713 BCE. So 070360 is only like August 21, 4521 BCE.....

Here is the USA Navy's page on it. I'm sure if you asked them how to do it, they'd tell you.

I don't know of a converter, but you might be able to find one by google...

NogDog

"Julian Date" is also used to refer to the practice of using the number of days in the year (1-365/366) instead of the month and day.

Anyway, there may be an easier way, but you could do something like (untested):

$year = substr($jdate, 0, 2);
$jday = substr($jdate, 3, 3);
$unixTime = strtotime('20'.$year.'-01-01 + ' . ($jday - 1) . ' days');
$date = date('Y-m-d', $unixTime);

laserlight

Does anyone have a function, or know where I can find one, for returning the Julian date for a date entered.

[man]GregorianToJD/man gives you the Julian day count, and then...

Julian Day Count to regular date?

You could try [man]JDToGregorian/man or [man]cal_from_jd/man.