[RESOLVED] finding a word in a string

[Sayian]

Im trying to build a function that checks to see if a string contains a bad word

function is_approp_input($string) {
	$bad_words = array('bad1','bad2','bad3','bad4');
	if(in_array($string,$bad_words)) {
		return false;
	} else {
		return true;
	}
}

Now if i had the string $string = "bad1ishere";

For some reason, this function will return true, not finding bad1 in the string. It should be returning false.

I probably am doing somthing wrong, so please advise.

[Weedpacket]

It returns true, because "bad1ishere" is not in the array.
You'll need a loop, and [man]strpos[/man].

[Sayian]

Thanks weedpacket

Ive added a loop, but for some reason i think im still doing somthing wrong

function is_approp_input($string) {
	$bad_words = array('xxx','xxx2','xxx3','xxx4');
	foreach($badwords as $word) {
		if(strpos($string,$word)) {
			return false;
		} else {
			return true;
	}
}
}

$string = "hhhhhh"; will return false

as will $string = "xxx";

Please advise.

[unisabilly]

Sayian wrote:

Thanks weedpacket

Ive added a loop, but for some reason i think im still doing somthing wrong

function is_approp_input($string) {
	$bad_words = array('xxx','xxx2','xxx3','xxx4');
	foreach($badwords as $word) {
		if(strpos($string,$word)) {
			return false;
		} else {
			return true;
	}
}
}

$string = "hhhhhh"; will return false

as will $string = "xxx";

Please advise.

try the following code ~
focus on substr_count and break .

function is_approp_input($string) {
	$bad_words = array('xxx','xxx2','xxx3','xxx4');
	foreach($badwords as $word) {
		if(substr_count($string,$word) > 0) {
			return false;
                           break;
		} else {
			return true;
	}
}
}

[Sayian]

Thanks for your help, but still no such luck.

The string xxxyou, returns true.

If you or anyone else has any feedback on this, or can see what im doing wrong, please advise.

[bpat1434]

How about eregi?

function is_approp_input($str)
{
	$bad_words = array('bad1', 'bad2', 'bad3', 'bad4', 'bad5');
	foreach($bad_words as $wrd)
	{
		if(eregi($wrd, $str))
		{
			return FALSE;
		}
		else
		{
			return TRUE;
		}
	}
}

Works for me....

[Sayian]

Thanks brett, that seemed to do the magic.

[bpat1434]

No problem.....