I can't display the variable value

[M__Abdel-Ghani]

If I write this code

$var="Sample text";
echo 'The variable is $var';

the output will be : The variable is $var
While I am expecting : The variable is Sample text
I know that I can write it in that way

echo 'The variable is'. $var;

But what about the first code ? why it's not displayed properly?
thanks in advance

[AIS4U]

M.Abdel-Ghani:

You forgot to read the chapter on concantenation.

You have enclosed your echo statement in quotes which means you are treating it as a string and therefore it will return the exact same string.

In your second code example, you have echoed the string and put quotes around it and then told php to join (.) whatever the variable $var represents.

[Houdini]

If you had written the second statement as

echo "The variable is $var":

It would have output The variable is Sample text try it to see. There is a difference when using single or double quotes in your example using single quotes you told PHP that $var was a literal ie $var but if you had used double quotes it would have used the value of $var instead of the literal $var.

[seaminem]

echo "The variable is $var.";