empty(),isset() cant get either to work

Paul_Ferrie

Hi guys.

I am trying to check to see if a reference var exsist's. if it does, do nothing. But if it does not. Create new var and create forlder with the new var.

if(!empty($_POST['tjRef'])){
$tjRef	= $_POST['tjRef'];
}else{
$tjRef	= substr($_FILES['Filedata1']['name'],0,5);
mkdir("../media/shoots/video/".$tjRef);
}

The mkdir still runs if if the var $tjRef is populated.

bpat1434

Have you looked at what empty() will evaluate to TRUE and FALSE?

The following things are considered to be empty:

"" (an empty string)
0 (0 as an integer)
"0" (0 as a string)
NULL
FALSE
array() (an empty array)
var $var; (a variable declared, but without a value in a class)

Paul_Ferrie

Yeh man i have the manual here! It's the first thing i check before posting anything php related.

I must be missing something somewhere. Will have a nother look over the code today.

Thanks

frost110

I have never gotten empty to work. Instead I would do this...

if(isset($_POST['tjRef']) && $_POST['tjRef'] != ""){
$tjRef    = $_POST['tjRef'];
}else{
$tjRef    = substr($_FILES['Filedata1']['name'],0,5);
mkdir("../media/shoots/video/".$tjRef);
}

--FrosT

Paul_Ferrie

Thank you both very much. Got it sorted now 🙂