Thanks for the help, but you arn't quite giving me the right answer.
With the $variable I gave, All I need returned Is CrazyArt.
Let me make this as detailed as possible.
$variable="
<html>
<head>
<titile>Example Site/Variable</title>
</head>
<body>
The site of great pieces of art you can find without any effort!<br>Our newest pieces are:<br>
<dev>CrazyArt</dev><br>
Underworld<br>
Peaceful<br>
<!-- Yes, only one will have the <dev> tag -->
<br>Copyright 2005 The example Site!
</body>
</html>";
//
//a preg_match with $variable that returns the result into $return
//
print $return;
//That will print "CrazyArt"
Sorry for the troubles.
-MasterDragon