[RESOLVED] Check for URL and omit form issues

[dmacman1962]

Hi All,

I have a products page that I wrote that loops thru my table and gets all the products and displays a "Buy Now" form for each item. The 'Buy Now' button sends the purchase to our shopping cart. It works great exept where I am trying to have it 'not' show the 'Buy Now' form for a product that links to multiple items.

In my table, I have a field called SpecialURL which has a default of 0 (zero).

So I do a test to see if that field is empty (show the form) or does it contain a URL (dont show the form).

 <?PHP if ($row[SpecialURL]==0) { ?>
(HTML FORM info}
<?PHP } else { end; } ?>

And the form shows up if the field has a zero or a URL in it?

I did a ...

<?PHP echo ($row[SpecialURL]); ?>

and for the empty fields I get a 0 (zero) and the fields with a URL in it, I get a 1 (one)???

Where is my logic off on this?

Thanks in advance,

Don

[crazychris]

note that ==0 also evaluates to false and empty string. try exact matching:

<?PHP if ($row['SpecialURL'] === 0) { ?>

[dmacman1962]

Hi cc,

I tried your suggestion and that did not work either. I just did not get any forms regardless of whether the field had a '0' or a link.

So I did this...

[php}
<?php if ($row[SpecialURL] =='0') { ?>
[/code]

and that worked.

Thanks,

Don