How would I code...

craigeves

I am wanting to code a small PHP script where if I typed a word into a text box and clicked on submit, the script would find a jpeg with the same name as what was typed in the text box and show it on the screen. If the jpeg doesn't exist it would return an error.

Can anyone help me as I really don't know where to start.

Thanks!

homer09001

simply make a table in a database with 3 fields id, imageurl and imagename

then mare a record for each image on you server then with the script do the following:

<?php
$server = "localhost";
$username = "username here";
$database = "database name here";
$password = "password here";
$tablename = "table name here";
$filename = $_POST['filename'];

print("<table border='1' cellpadding='2' cellspacing=0><tr><th width='48'>ID</th><th>Image Name<th>Image Url</th></tr>");

$conn = mysql_connect($server, $username, $password);
mysql_select_db = ($tablename, $conn);

$query = mysql_query("SELECT * FROM $tablename WHERE imagename='$filename');

while ($results = mysql_fetch_array($query))
{
extract ($results);
$temp1 = $row['id'];
$temp2 = $row['imagename'];
$temp3 = $row['imageurl'];

echo "<tr><td>$temp1</td><td>$temp2</td><td>$temp3</td>";

?>

this should work not 100% sure my php knowledge isnt amazing

justsomeone

if you just want to use the input field as filename, you don't need a database.

<?php
//Treat this code with caution - no PHP environment here to test it

// Change this to the correct directory
$filesdir = "/var/www/imagefiles/";

$suffix = ".jpg";

// Change the below to match the fieldname on your form
if (isset($_POST['fieldname'])){

$requiredfile = $filesdir.$_POST['fieldname'].$suffix;

if (file_exists($requiredfile) && is_readable($requiredfile)){

    $fp = fopen($requiredfile, 'rb');

    // send the right headers
    header("Content-Type: image/jpg");
    header("Content-Length: " . filesize($requiredfile));

    // dump the picture
    fpassthru($fp);
    fclose($fp);
}
}
?>

craigeves

Hi - thanks for this, but i dont think this is what i am really after... i want something simple that does not need a database.

I want to drop an image into say the /images/ folder via ftp on my server, and when you type 'hellomister' (for example) in text box, if the hellopmister.jpg is in the images folder then it displays the image, but if its not there then it says sorry... no image found.

thanks again though.

homer09001 wrote:

simply make a table in a database with 3 fields id, imageurl and imagename

then mare a record for each image on you server then with the script do the following:

<?php
$server = "localhost";
$username = "username here";
$database = "database name here";
$password = "password here";
$tablename = "table name here";
$filename = $_POST['filename'];

print("<table border='1' cellpadding='2' cellspacing=0><tr><th width='48'>ID</th><th>Image Name<th>Image Url</th></tr>");

$conn = mysql_connect($server, $username, $password);
mysql_select_db = ($tablename, $conn);

$query = mysql_query("SELECT * FROM $tablename WHERE imagename='$filename');

while ($results = mysql_fetch_array($query))
{
extract ($results);
$temp1 = $row['id'];
$temp2 = $row['imagename'];
$temp3 = $row['imageurl'];

echo "<tr><td>$temp1</td><td>$temp2</td><td>$temp3</td>";

?>

this should work not 100% sure my php knowledge isnt amazing

craigeves

Hi... thanks for this. This is better - but i cant get it to work :

(

justsomeone wrote:

if you just want to use the input field as filename, you don't need a database.

<?php
//Treat this code with caution - no PHP environment here to test it

// Change this to the correct directory
$filesdir = "/var/www/imagefiles/";

$suffix = ".jpg";

// Change the below to match the fieldname on your form
if (isset($_POST['fieldname'])){

$requiredfile = $filesdir.$_POST['fieldname'].$suffix;

if (file_exists($requiredfile) && is_readable($requiredfile)){

    $fp = fopen($requiredfile, 'rb');

    // send the right headers
    header("Content-Type: image/jpg");
    header("Content-Length: " . filesize($requiredfile));

    // dump the picture
    fpassthru($fp);
    fclose($fp);
}
}
?>

My code is

<?php
//Treat this code with caution - no PHP environment here to test it

// Change this to the correct directory
$filesdir = "/home/workm8/public_html/proof/";

$suffix = ".jpg";

// Change the below to match the fieldname on your form
if (isset($_POST['password'])){
$requiredfile = $filesdir.$_POST['password'].$suffix; 

    if (file_exists($requiredfile) && is_readable($requiredfile)){ 

            $fp = fopen($requiredfile, 'rb'); 

            // send the right headers 
            header("Content-Type: image/jpg"); 
            header("Content-Length: " . filesize($requiredfile)); 

    // dump the picture 
    fpassthru($fp); 
    fclose($fp); 
} 
}
?>

with the page before being really simple in:

<form name="password" method="post" action="proof.php">
<input name="password" type="text" id="password">
<input type="submit" name="Submit" value="Submit">
</form>

Can you help again? My intital page is index.php and the script is proof.php

Thanks

justsomeone

Sadly, you need to debug it, and I can't do it form here.

I would start by doing an

echo "The required file is [".$requiredfile."]";

On the line after where you assign the value to $requiredfile.

This should echo out what PHP thinks the file is called.

If this line doesn't appear at all when you run the program, it's because the "if(isset" failed. You need to doublecheck what's going on there. Maybe echo the value of $_POST["password"];

If the line appears but the value between the square brackets doesn't match the full path to the image file, you need to change some of the variables in the script to get it right.

If the line appears and the value between the square brackets is right but nothing else happens, that file may not be readable - check the permissions.

If the line appears and is correct, and you get an error saying "unable to send headers", then all would appear to be fine, it's just that the echo you just put in is breaking the "headers" commands.

craigeves

The error i get is

Parse error: parse error, unexpected T_VARIABLE in /home/workm8/public_html/proof/proof.php on line 12

justsomeone wrote:
Sadly, you need to debug it, and I can't do it form here.

I would start by doing an
echo "The required file is [".$requiredfile."]";
On the line after where you assign the value to $requiredfile.

This should echo out what PHP thinks the file is called.

If this line doesn't appear at all when you run the program, it's because the "if(isset" failed. You need to doublecheck what's going on there. Maybe echo the value of $_POST["password"];

If the line appears but the value between the square brackets doesn't match the full path to the image file, you need to change some of the variables in the script to get it right.

If the line appears and the value between the square brackets is right but nothing else happens, that file may not be readable - check the permissions.

If the line appears and is correct, and you get an error saying "unable to send headers", then all would appear to be fine, it's just that the echo you just put in is breaking the "headers" commands.

homer09001

try replaing this

<?php 
$requiredfile = $filesdir.$_POST['password'].$suffix;

with:

$requiredfile = $filesdir.$password.$suffix;

and add

$password = $_POST['password'];

after

$suffix = ".jpg";

so it should look like:

<?php 
//Treat this code with caution - no PHP environment here to test it 

// Change this to the correct directory 
$filesdir = "/home/workm8/public_html/proof/"; 

$suffix = ".jpg"; 
$password = $_POST['password'];

// Change the below to match the fieldname on your form 
if (isset($_POST['password'])){ 

$requiredfile = $filesdir.$password.$suffix; 

if (file_exists($requiredfile) && is_readable($requiredfile)){ 

$fp = fopen($requiredfile, 'rb'); 

// send the right headers 
header("Content-Type: image/jpg"); 
header("Content-Length: " . filesize($requiredfile)); 

// dump the picture 
fpassthru($fp); 
fclose($fp); 
} 
} 
?>

craigeves

That works now... is there anyway i can get it to echo "no image here" if it doesn't exist?

I really appreciate your help.

Oh - and 1 more thing - if I run this code in Safari on a Mac it downloads the php file instead of loading the image. Can I do anything to combat this. It works fine in other browsers.

homer09001 wrote:

try replaing this

<?php 
$requiredfile = $filesdir.$_POST['password'].$suffix;

with:

$requiredfile = $filesdir.$password.$suffix;

and add

$password = $_POST['password'];

after

$suffix = ".jpg";

so it should look like:

<?php 
//Treat this code with caution - no PHP environment here to test it 

// Change this to the correct directory 
$filesdir = "/home/workm8/public_html/proof/"; 

$suffix = ".jpg"; 
$password = $_POST['password'];

// Change the below to match the fieldname on your form 
if (isset($_POST['password'])){ 

$requiredfile = $filesdir.$password.$suffix; 

if (file_exists($requiredfile) && is_readable($requiredfile)){ 

$fp = fopen($requiredfile, 'rb'); 

// send the right headers 
header("Content-Type: image/jpg"); 
header("Content-Length: " . filesize($requiredfile)); 

// dump the picture 
fpassthru($fp); 
fclose($fp); 
} 
} 
?>

homer09001

<?php 
//Treat this code with caution - no PHP environment here to test it 

// Change this to the correct directory 
$filesdir = "/home/workm8/public_html/proof/"; 

$suffix = ".jpg"; 
$password = $_POST['password']; 

// Change the below to match the fieldname on your form 
if (isset($_POST['password'])){ 

$requiredfile = $filesdir.$password.$suffix; 

if (file_exists($requiredfile) && is_readable($requiredfile)){ 

$fp = fopen($requiredfile, 'rb'); 

// send the right headers 
header("Content-Type: image/jpg"); 
header("Content-Length: " . filesize($requiredfile)); 

// dump the picture 
fpassthru($fp); 
fclose($fp); 
} 
else
{
echo("Sorry no image with that name");
} 
}
?>

try that

homer09001

ohh and the mac thing i aint a clue sorry im a windows user wouldnt touch a mac with a barge poll lol