[RESOLVED] Help with image scaler

[tripodkid]

Hello!

This script is driving me crazy! 😕

I'm retreving fullsize images from a db and trying to return them into a table as thumbnails.

$image_path echos the correct path to the image but $thumbnail always echos 1.

Thanks for you help! 🙂

<?php 

do {
// Constants 
define(MAX_WIDTH, 300);
define(MAX_HEIGHT, 300);

//Get image
$image_path = $row_rs_images['image_path'];

// Load image
$img = null;
$ext = strtolower(end(explode('.', $image_path)));
if ($ext == 'jpg' || $ext == 'jpeg') {
    $img = @imagecreatefromjpeg($image_path);
	} else {
		echo "This is not a jpeg image";
		exit;
	}

// If an image was successfully loaded, test the image for size
if ($img) {

// Get image size and scale ratio
$width = imagesx($img);
$height = imagesy($img);
$scale = min(MAX_WIDTH/$width, MAX_HEIGHT/$height);

// If the image is larger than the max shrink it
if ($scale < 1) {
    $new_width = floor($scale*$width);
    $new_height = floor($scale*$height);

    // Create a new temporary image
    $tmp_img = imagecreatetruecolor($new_width, $new_height);

    // Copy and resize old image into new image
    imagecopyresized($tmp_img, $img, 0, 0, 0, 0, 
                     $new_width, $new_height, $width, $height);
    imagedestroy($img);
    $img = $tmp_img;        
}    
}

$thumbnail = imagejpeg($img, '0' ,'100'); 
echo '<table width="65%" border="1" cellspacing="0" cellpadding="3">
  <tr>
    <td width="31%"><div align="center"><img src='. $thumbnail. '/>	
    <td width="68%">&nbsp<br /><br />
	</td></td>
  </tr>
</table> 
<p>&nbsp;</p>';
         } while ($row_rs_images = mysql_fetch_assoc($rs_images)); 

?>

[bodzan]

You will have to ask a server to create a picture first with [man]imagecreatetruecolor[/man] and after that to have it define a proper header as in...

header ("Content-type: image/jpeg");

...before you can show the image in your browser.

I rarelly use these functions but I figure you might want to create a new file to show a picture and to call it from a page where you want that picture shown. Like:

<img src="pic.php?id=1">

...where id would be an id of the thumbnail you want to show...

[codefetch]

If you want to display images using <img src='. $thumbnail. '/> you'll have to write-out the thumbnails to disk somewhere where your web server can serve them from.

I did a codefetch search for image thumbnail and found this example of uploading images and creating thumbnails from the book Beginning PHP5, Apache, and MySQL Web Development. The text is hot-linked to PHP documentation so you can click on PHP commands in the code to see the syntax. See for example how they use imagejpeg.