[RESOLVED] Passing a dynamic url and stripping the last trailing slash

Steve_B2

Apologies if this has already been asked and answered previously, I did use the search function but couldn’t find an answer in the results.

I am using this on a gallery and I am calling the different album urls dynamically using “getAlbumLinkURL” . This is working great but I also have a slideshow option that I would like to include which needs to be invoked by using the full URL + “&slideshow”

The problem is that I am using Mod_rewrite to give nice urls and the nice urls are correctly being written with a final trailing slash.

Current example of the url would be

www.mysite/mygallery/albumname/

Where the “albumname” changes according to the gallery being viewed.

I need to be able to get that url and strip the trailing slash from the end and then add “&slideshow”. This new URL will then be coded to a link connected with the slideshow. Is there some php code that I can add that is able to do this?

Any help would be very appreciated.

rincewind456

trim() will do that for you something like

<?php
 $name= 'www.mysite/mygallery/albumname/';
$name = trim($name, '/'); // trims the / from the end
$extra = '&slideshow';
echo $name.$extra;
?>

willl out put

www.mysite/mygallery/albumname&slideshow

Steve_B2

Thanks for the quick reply, unfortunately I think my understanding of php is not good enough and I may have not described the variables properly.

The "getGalleryIndexURL()" is the call to the album address which is variable and so cannot be coded as a direct link to the page as in your example above. Its this variable that needs to be called and then the final slash removed.

Using your code and inserting my variable may hep you understand my poor attempt at both coding and explaining the problem.

<?php
$name= 'getGalleryIndexURL()';
$name = trim($name, '/'); // trims the / from the end
$extra = '&slideshow';
?>


<a href="<?=$name;?>" title="View as slideshow">View as slideshow</a>

Obviously the above gives me a url links that looks like ...
http://www.mysite.com/images/Animals/getGalleryIndexURL()

when I need it to be
http://www.mysite.co.uk/images/Animals&slideshow

does that help any?

Sorry for my bad explination

rincewind456

That would probably work a lot better witout the single quotes around getGalleryIndexURL(), why have you put them there? By doing that you're passing a string to the variable $name, rather than the output of the function.

laserlight

I need to be able to get that url and strip the trailing slash from the end and then add “&slideshow”.

The thing is, if you are appending a query string, it starts with '?', not '&'. The ampersand is used to separate name/value pairs in the query string, not to mark the start of the query string.

But now,
http://www.example.com/mygallery/albumname/?slideshow=1
is as valid as:
http://www.example.com/mygallery/albumname?slideshow=1

Steve_B2

Thanks again for the reply, as I said I am new to this and still learning...

I tried the method above without the single ' with double " and all other ways I could think of but the closest I could get was it doubling up on the last two directories..

so I was getting /images/albumname/images/albumname&slideshow

This then gave me a clue as to what was happening and from there I managed to solve the problem with the following code.

<?php
$name = "http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];
$name = trim($name, '/'); // trims the / from the end
$extra = '&slideshow';
?>

and then to output the link

   [code=php]<a href="<?=$name.$extra;?>" title="View as slideshow">View as slideshow</a>[/code]

So all is working great now. 🙂

Thank you so much for your help, there is no way I would have solved the problem without your guidance!!