PHP to Print html code syntax problems

[djwinder]

Hi
here is a small section of code which when executed does so without php reporting an error but the image doesnt display. The variables $thumbpath and $currimage both contain valid file paths which when echoed are both C:/web/root/images/thumbs/DSCF2496.JPG. any ideas why the code isnt displaying the file?

<?php 
if ($thumbpath) { print ('<img src="$thumbpath">'); } else
{ print ('<img src="$currimage">'); }  

?>

[rincewind456]

Try this

if ($thumbpath) { print ('<img src="'.$thumbpath.'">'); } else
{ print ('<img src="'.$currimage.'">'); }

[HP400]

PHP will put the value of variables when they are inside "dobule quotes"
However, anything in single quotes is taken as is.

[djwinder]

i have the code exactly as in rincewind 456 post yet the error still occures the variable definatley contains the file path so i am very confused as to what the problem might be

[Houdini]

Is it possible that there is a typo in $thumbpath or is the path correct, try to echo the $thumbpath as what you are setting it (as in <img src="image/some.gif">) and if the image doesn't show then the path might be wrong.

[djwinder]

thanks for the replay, as i mentioned in my initial post the echoed values are correct paths and it will display if the html to display the image is written outside of the if / else statment however the statment fails.

[herve]

<?PHP

  if ($thumbpath) 
  { 
  	print "<img src=\"$thumbpath\">"; 
  } 
  else
  { 
  	print "<img src=\"$currimage\">"; 
  }  

?>