Adding form values

[BEFOR]

I have two menus, one 'Thou' representing 1,000's and another ' Hund' for hundreds.

How can these be added for insert into a single table column. "Thouhundreds"

On a single form insert. (no javascript)

<select name="Thou" id="Thou">
<option value="">&nbsp;&nbsp;000's</option>
<option value="15000">&nbsp;&nbsp;15,</option>
<option value="16000">&nbsp;&nbsp;16,</option> </select>

<select name="Hund" id="Hund">
<option value="">00</option>
<option value="50">50</option>
<option value="100">100</option>
</select>

[makeshift]

Wtf? Your question is cryptic at best and I'm looking at your form and wondering why the hell you would do something like that.

Are you just talking about a regular for loop?

$html = "<select name="thouHundreds">
              <option>Select One Below</option>";
for($i = 10; $i < 21; $i++) // 10 & 21 can be replaced with anything in the tens of thousands
{
     for($j = 0; $j < 101; $j += 50) // going 0, 50, 100 like your form says. again, i have no idea why you would do that
     {
          $val = 1000 * $i + $j;
           $html .= "<option value=" . $val . ">" . $val . "</option>";
      } 

} 

$html .= "</select>";

echo $html;

[BEFOR]

Cryptic? You really lost me.

There are two drop menus, their selected values are being added to be inserted into a table column.

Why would I want to do this? To achieve many different combinations with the menus. The hundreds are added to thousands.

[bradgrafelman]

Uh, well, why not just add the two?

$value = intval($_POST['Thou'] + $_POST['Hund']);